Find the HCF of the following by the method of prime factorisation.
a. 42and 63
b. 25 and 90
c. 18,24,32
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Answer:a.21 b.5 c.2
Step-by-step explanation:
a.42= 2×3×7×1
63= 3×3×7×1
Common factors= 3×7×1= 21
b. 25= 5×5×1
90= 2×5×3×3×1
Common factors= 5×1= 5
c. 18= 3×3×2×1
24= 3×2×2×2×1
32= 2×2×2×2×2×1
Common factors= 2×1= 2
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