Question

Find the HCF of the following by the prime factorization method: (3) a) 30, 45 and 54 Ans: b) 42, 55, 56 Ans: c) 36 and 48 Ans:

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Answer 1

Answer:

(a)3   (b)0  (c) 4

Step-by-step explanation:

Answer 2

Answer:

a) 3

b) 1

c) 12

Step-by-step explanation:

a) 30,45 & 54

prime factors of

      30 = 2 x 3 x 5

      45 = 3 x 3 x 5

      54 = 2 x 3 x 3 x 3

Common prime factors of 30, 45 & 54 = 3

HCF of 30,45 & 54 = 3

b) 42, 55, 56

prime factors of

      42 = 2 x 3 x 7

      55 = 5 x 11

      56 = 2 x 2 x 2 x 7

Common prime factors of  42, 55, 56 = No number except 1

HCF of  42, 55, 56  = 1

42, 55, 56  are co-prime numbers

c) 36 and 48

prime factors of

      36 = 2 x 2 x 3 x 3

      48 = 2 x 2 x 2 x 2 x 3

Common prime factors of  36 and 48 =  2 x 2 x 3

HCF of  36 and 48  =  12