find the HCF of the following monomial -2x^ y^3 z,-8xy^4 z^2 and -14x^3 y^3 z^3
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Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 8, 12 and 20.
Since, 8 = 2 × 2 × 2 = 23, 12 = 2 × 2 × 3 = 22 × 31 and 20 = 2 × 2 × 5 = 22 × 51
Therefore, the H.C.F. of 8, 12 and 20 is 4
Now, the variables x and y are present in all the quantities. Out of these the highest common power of x is 2 and the highest common power if y is 1.
Therefore, the required H.C.F. = 4x2y1 = 4x2y
The method by which the H.C.F. of the monomials are determined can be formulated as follows:
(i) The H.C.F. of the numerical coefficients are to be determined at first.
(ii) Then the variables are to be written beside the coefficient with their highest common power or greatest common power.
Note:
According to the well known definition of H.C.F. or G.C.F. each term should be divisible by it, but there should be no common factor in the quotients thus obtained.
The fact can be verified, for example 2 we can observe that;
8x2y/4x2y = 2 12x3y2/4x2y = 3xy
20x2y2z/4x2y = 5yz
Here, the quotients are 2, 3xy and 5yz which have no common factor between them.
Similarly after finding the highest common factor of monomials by factorization we can verify the above fact.
Hope it helps u carry on learning
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