Question

find the HCF of the following number 12 45 75​

Answer 1

SolutioN :

Let's,

• N1 = 12.
• N2 = 45.
• N3 = 75.

★ Now, Let's Find the HCF of N1 , N2 and N3.

# For N1.

$\begin{array}{r | l} 2 & 12 \\ \cline{2-2} 2 & 6 \\ \cline{2-2} 3 & 3 \\ \cline{2-2} & 1 \end{array}$

# For N2.

$\begin{array}{r | l} 5 & 45 \\ \cline{2-2} 3 & 9 \\ \cline{2-2} 3 & 3 \\ \cline{2-2} & 1 \end{array}$

# For N3.

$\begin{array}{r | l} 5 & 75 \\ \cline{2-2} 5 & 15 \\ \cline{2-2} 3 & 3 \\ \cline{2-2} & 1 \end{array}$

12 → 2 * 2 * 3.

45→ 5 * 3 * 3.

75 → 5 * 5 * 3

HCF = ( 12 , 45 , 75 ) = 3.

Therefore, the HCF of 12 , 45 , 75 is 3.

Answer 2

$\huge \fbox \pink{❥Answer}$

3

Explanation:

hope it will help you buddy