Find the hcf of the following number by division method 129,215 and 387
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Answer:
3(129
43(43
(1
therefore ,129=3×43×1.
5 (215
43(43
(1
therefore, 215= 5×43×1.
3(387
3 (129
3 (43
43(43
(1
Therefore, 387=3×3×3×43×1.
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