find the HCF of the following numbers by long division method. 288,576;345,506;230,280
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(i) 288,576
= 288
Because 576 ÷ 288 = 2 Then 288 is the h.c.f. of 288 and 576
(ii) 345,506
= 23
Because 506 ÷ 345 = 1 but remainder 161 then 345 ÷ 161 = 2 but remainder is 23 then 161 ÷ 23 = 7 Then 23 is the h.c.f. of 345 and 506.
(iii) 230,280
= 10
Because 280 ÷ 230 = 1 but remainder is 50 then 230 ÷ 50 = 4 but remainder is 30 then 50 ÷ 30 = 1 but remainder is 20 then 30 ÷ 200 = 1 but remainder is 10 then 20 ÷ 10 = 2 Then 10 is h.c.f. of 230 and 280
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= 288
Because 576 ÷ 288 = 2 Then 288 is the h.c.f. of 288 and 576
(ii) 345,506
= 23
Because 506 ÷ 345 = 1 but remainder 161 then 345 ÷ 161 = 2 but remainder is 23 then 161 ÷ 23 = 7 Then 23 is the h.c.f. of 345 and 506.
(iii) 230,280
= 10
Because 280 ÷ 230 = 1 but remainder is 50 then 230 ÷ 50 = 4 but remainder is 30 then 50 ÷ 30 = 1 but remainder is 20 then 30 ÷ 200 = 1 but remainder is 10 then 20 ÷ 10 = 2 Then 10 is h.c.f. of 230 and 280
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Answer:
hcf=288
hcf=23
hcf=10
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