Find the HCF of the following numbers by prime factorisation and continued division
method?
i 18, 27, 36
ii. 106, 159, 265
111 10, 35, 40
iv. 32, 64, 96, 128
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Step-by-step explanation:
HCF by prime Factorization :
(1) 18 , 27 , 36
18 = 2 x 3 x 3
27 = 3 x 3 x 3
36 = 2 x 2 x 3 x 3
HCF = 3 x 3 = 9
(2) 106 , 159 , 265
106 = 2 x 53
159 = 3 x 53
265 = 5 x 53
HCF = 53
(3) 10 , 35 , 40
10 = 2 x 5
35 = 5 x 7
40 = 2 x 2 x 2 x 5
HCF = 5
(4) 32 , 64 , 96 , 128
32 = 2 x 2 x 2 x 2 x 2
64 = 2 x 2 x 2 x 2 x 2 x 2
96 = 2 x 2 x 2 x 2 x 2 x 3
128 = 2 x 2 x 2 x 2 x 2 x 2 x 2
HCF = 32
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