Question

Find the HCF of the following numbers by prime factorisation and continued division
method?
i 18, 27, 36
ii. 106, 159, 265
111 10, 35, 40
iv. 32, 64, 96, 128​

Answer 1

Step-by-step explanation:

HCF by prime Factorization :

(1) 18 , 27 , 36

18 = 2 x 3 x 3

27 = 3 x 3 x 3

36 = 2 x 2 x 3 x 3

HCF = 3 x 3 = 9

(2) 106 , 159 , 265

106 = 2 x 53

159 = 3 x 53

265 = 5 x 53

HCF = 53

(3) 10 , 35 , 40

10 = 2 x 5

35 = 5 x 7

40 = 2 x 2 x 2 x 5

HCF = 5

(4) 32 , 64 , 96 , 128

32 = 2 x 2 x 2 x 2 x 2

64 = 2 x 2 x 2 x 2 x 2 x 2

96 = 2 x 2 x 2 x 2 x 2 x 3

128 = 2 x 2 x 2 x 2 x 2 x 2 x 2

HCF = 32

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Answer 2

Answer:

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Step-by-step explanation:

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