Find the HCF of the following numbers by prime factorisation and continued division
method?
i 18, 27, 36
ii. 106, 159, 265
111. 10, 35, 40
iv. 32, 64, 96, 128
nn
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Step-by-step explanation:
1. 18, 27, 36
18 = 1 2 3 6 9 18
27 = 1 3 9 27
36 = 1 2 3 4 9 12 18 36
HCF = 9
2. 106, 159, 265
106 = 1 2 53 106
159 = 1 3 53 159
265 = 1 5 53 265
HCF = 53
3. 10, 35, 40
10 = 1 2 5 10
35 = 1 5 7 35
40 = 1 2 4 5 8 10 20 40
HCF = 5
4. 32, 64, 96, 128
32 = 1 2 4 8 16 32
64 = 1 2 4 8 16 32 64
96 = 1 2 3 4 6 8 12 16 24 32 48 96
128 = 1 2 4 8 16 32 64 128
HCF = 32
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