Question

Find the HCF of the following numbers by prime factorisation and continued division
method?

32, 64,96, 128​

Answer 1

Answer:

HCF = 32

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Step-by-step explanation:

32: 2×2×2×2×2

64: 2×2×2×2×2×2

96: 2×2×2×2×2×3

128: 2×2×2×2×2×2×2

HCF: 2×2×2×2×2 = 32

Solution 2

32,64,96,128

1st two numbers 32 and 64

32 | 64 ( 2

64

______

0

HCF of 32 and 64 is 32

Now HCF 32 and 3rd number 96

32 | 96 ( 3

96

______

0

HCF of 32 and 96 = 32

Now hcf 32 and last nuber 128

32 | 128 ( 4

128

______

0

hcf of 32 and 128 is 32

Well the hcf of 32,64 96 and 128 is 32

All the best

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