English, asked by anujjaiswal39, 7 months ago


Find the HCF of the following numbers by the prime factorisation method :-
40, 56, and 64​

Answers

Answered by prakriti04
7

Answer:8

Explaination:

we can find the HCF as follows:

first we will divide 40,56 and 64 in the hcf table by 2 .So we will get the result 20,28,32 respectively .As we can se that the numbers are still divisible by two so we will repeat the steps .And now we will get 10,14,16 respectively.We can see the numbers are still divisible by 2 so we will repeat the steps and we will 5,7,8 respectively.These numbers are all not divisible by 2 so we will stop dividing them .Now we will multiply the divisor we have used earlier .2*2*2=8 .Thus,8 is the HCF of 40,56 and 64 .

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