Find the HCF of the following numbers,using prime factorisation of 24,40 and 56
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Hey friend!!
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This is the answer
It is in the attachment below.
The HCF of 24, 40, 56
24= 2x 2x 2x 3x 1
40= 2x 2x 2x 5x 1
56= 2x 2x 2x 7x 1
HCF= 2x2x2x1
=8
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