Question

find the hcf of the following numbers using the prime factorization method d.144, 372 sai.​

Answer 1

$\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}$

$\boxed {H.C.F.(144,372)=12}$

$\boxed {\underline {\mathbb {TO\:FIND:-}}}$

HCF of 144 and 372

$\boxed {\underline {\mathbb {FORMULA\:USED:-}}}$

factorisation

$\boxed {\underline {\mathbb {SOLUTION:-}}}$

factors of 144 are:-

$\begin{array}{r | l}2 & 144 \\\cline {2-2} 2 & 72 \\\cline {2-2} 2&36 \\\cline {2-2} 2&18 \\\cline {2-2} 3&9 \\\cline {2-2} 3 & 3 \\\cline {2-2} & 1\end{array}$    

factors of 372 are:-

$\begin{array}{r | l}2 & 372 \\\cline{2-2} 2 & 186 \\\cline{2-2} 3&93 \\\cline{2-2} 31&31 \\\cline{2-2} & 1\end{array}$

here

$144=2*2*2*2*3*3\\372=2*2*3*31$

so common in both are $2*2*3$ $\implies 12$

hence HCF of 144 and 372 is $\boxed{12}$

⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔ ⇔

Answer 2

XaItzAnvayaXx ne accha answer diya hai use brainlist bana do aur use follow kar lo