Math, asked by Raveendraadusumilli, 8 months ago

find the hcf of the following polynomials 3(x²-9)(x+4)and 12(x-3)²

Answers

Answered by Sankarshana
17

Answer:

3 ( x - 3 )

Step-by-step explanation:

Let a = 3(x²-9)(x+4) and b = 12(x-3)²

a = 3 (x²-9)(x+4)

a = 3 (x-3)(x+3)(x+4)                 (a^{2} - b^{2} = (a - b)(a + b) )

b = 12 (x-3)(x-3)

By comparing the factors, the HCF is clearly 3 (x-3)

HOPE YOU UNDERSTAND

Answered by ganesh9337
8

Answer:

3 ( x - 3 )

Step-by-step explanation:

Let a = 3(x²-9)(x+4) and b = 12(x-3)²

a = 3 (x²-9)(x+4)

a = 3 (x-3)(x+3)(x+4)                 ( -  = (a - b)(a + b) )

b = 12 (x-3)(x-3)

By comparing the factors, the HCF is clearly 3 (x-3)

HOPE YOU UNDERSTAND

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