Math, asked by elizabethdias, 8 months ago

find the HCF of the following set of numbers
a) 16 , 24 , 40

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Answers

Answered by sakshamshukla38
1

Answer:

8

Step-by-step explanation:

First, find the factors of all the three numbers.

16 = 2 x 2 x 2 x 2

24 = 3 x 2 x 2 x 2

40 = 5 x 2 x 2 x 2

Therefore the HCF = 2 x 2 x 2

= 8

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Answered by farheeneqbal2008
1

Step-by-step explanation:

First we will find the factors:

16 = 2×2×2×2

24 = 2×2×2×3

40 = 2×2×2×5

Now we have to find the common factor:

The common factors are 2, 2, 2

HCF of 16, 24, 40 = 2×2×2

= 8

So the HCF is 8.

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