Question

.. Find the HCF of the following sets of numbers by short division method:
a) 85, 136
b) 242, 88
c) 32, 128,96
d) 70, 105, 175, 65​

Answer 1

Answer:

hcf of the following

a)17

b)22

c)32

d)35

Answer 2

Answer:

1) 85= 5*17

136 = 2*2*2*17

HCF= 17

2) 242=2*11*11

88=2*2*2*11

HCF=2*11=22

3)32=2*2*2*2*2

128=2*2*2*2*2*2*2

96=2*2*2*2*2*3

HCF=2*2*2*2*2 = 32

4)70 = 2*5*7

105= 3*5*7

175= 5*5*7

65= 5*13

HCF = 35

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