find the HCF of the following terms 32x³y³and 24x²y²
Answers
Answer:
26 = 2 x 13
91 =7 x 13
HCF = 13
LCM =2 x 7 x 13 =182
Product of two value 26 x 91 = 2366
Product of HCF and LCM 13 x 182 = 2366
Hence, product of two numbers = product of HCF × LCM
(ii)
510 = 2 x 3 x 5 x 17
92 =2 x 2 x 23
HCF =2
LCM =2 x 2 x3 x 5 x 17 x 23 = 23460
Product of both values 510x92 = 46920
Product of HCF and LCM 2x23460 =46920
Hence, product of two numbers = product of HCF × LCM
(iii)
336 = 2 x 2 x 2 x 2 x 3 x 7
54 = 2 x 3 x 3 x 3
HCF = 2 x 3 = 6
LCM = 2 x 2 x 2 x 2 x 3 x 3 x 3 x 7 =3024
Product of number 336 x 54 =18144
Product of HCF and LCM 6 x 3024 = 18144
Hence, product of two numbers = product of HCF × LCM