. Find the HCF of the given numbers:
(2) 42, 36 (b) 21, 40
(e) 25, 125 (f) 17, 27
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(a)
- 42 , 36
- 42 = 2 × 3 × 7
- 36 = 2 × 2 × 3 × 3
- HCF = 2 × 3
- HCF = 6
(b)
- 21 , 40
- 21 = 3 × 7 × 1
- 40 = 2 × 2 × 2 × 5 × 1
- HCF = 1
(c)
- 25 , 125
- 25 = 5 × 5
- 125 = 5 × 5 × 5
- HCF = 5 × 5
- HCF = 25
(d)
- 17 , 27
- 17 = 17 × 1
- 27 = 3 × 3 × 3 × 1
- HCF = 1
LAKSHMINEW:
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