Question

Find the HCF of the given numbers 90, 108 and 126​

Answer 1

${\huge{\bold{\underline{Answer:-}}}}$

90 = 2 * 45 = 2 * 3 * 15 = 2 * 3 * 3 * 5. Since 2, 3, and 5 are prime numbers, they are prime factors of 90.

108 = 2 * 54 = 2 * 2 * 27 = 2 * 2 * 3 * 9 = 2 * 2 * 3 * 3 * 3. So, 2 and 3 are prime factors of 108.

126 = 2 * 63 = 2 * 9 * 7 = 2 * 3 * 3 * 7. So 2, 7, and 3 are the prime factors of 126.

Hence, the HCF of 90, 108 and 126 is 18.

Answer 2

Step-by-step explanation:

2 | 90

5| 45

3 | 9

3 | 3

1 | 1

= 1

90 =2×5×3×3×1

108

2 | 108

2 | 54

2 | 27

3 | 9

3 | 3

1 | 1

= 1

108 = 2×2×2×3×3×1

126

2 | 126

3 | 63

3 | 21

3 | 7

7 | 1

126=2×3×3×3×7×1