Question

Find the HCF of the numbers in each of the following using the prime factorization Method:

a. 144 and 198
b. 396 and 1080
c. 144, 180 and 192​

Answer 1

Answer:

a.6 b.44 c.12

Step-by-step explanation:

a. 144 = 2^2 * 3^2   ,   198 = 2*3*11

HCF= 2*3= 6

b. 396 = 2^2*3*11    ,   1080 = 2^2*5^2*11

HCF = 2^2*11 = 44

c. 144 = 2^2 * 3^2    ,   180 = 2^2*3^2*5    ,    192 = 2^6*3

HCF = 2^2*3 = 12

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Answer 2

Step-by-step explanation:

a.6 b.44 c.12

Step-by-step explanation:

a. 144 = 2^2* 3^2, 198 2 311

HCF 23=6

b. 396 = 2^2'3-11 1080 = 2^2"5^2 11

HCF = 2^2*11 = 44

c. 144 = 2^2 *3^2

192 = 26'3

HCF = 2^2"3 = 12 =

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1

180 =