find the HCF of the numbers in each of the folowing,using the prime factorisation method: 84,120,138
Answers
Answered by
3
Answer:
2
please mark it as brainiest answer
84=42
120=60
138=69
abhinavjha86:
need method
Answered by
3
Step-by-step explanation:
2 by 84=42
2 by 42=21
3 by 21=7
7 by 7=1
2 by 120=60
2 by 60=30
2 by 30=15
3 by 15=5
5 by 5=1
2 by 138=69
3 by 69=23
23 by 23=1
84=2×2×3×7
120=2×2×2×3×5
138=2×3×23
common factors of 84,120and138=
2×3=6
Similar questions
Social Sciences,
7 months ago
CBSE BOARD XII,
7 months ago
English,
7 months ago
Math,
1 year ago
Math,
1 year ago