Question

find the hcf of the terms of the expression 2b cube c+4b cube c square +16 b cube c cube. also write the factors of the above expression ​

Answer 1

Answer:the HCF is 2b2C and factors are 2b2C and b+2b2c +8c

Step-by-step explanation:

2b3c+4b4c2+16b2c2

Now take a common

2b2c(b+2b2c+8c)

HCF=2b2C factors=2b2Candb+2b2c+8c

Answer 2

The HCF is 2bc.

The factors are $2bc$ and $b^2+2b^2c+4c^2$

Step-by-step explanation:

Given : Expression $2b^3c+4b^3c^2+16bc^3$

To find : Find the HCF of the terms of the expression and also write the factors ?

Solution :

HCF is the highest common factors.

$2b^3c=2\times b\times b\times b\times c$

$4b^3c^2=2\\times 2\times b\times b\times b\times c\times c$

$16bc^3=2\times2\times 2\times 2\times b\times c\times c\times c$

The HCF is $2\times b\times c=2bc$

Expression $2b^3c+4b^3c^2+16bc^3$

Taking '2bc' common,

$2bc(b^2+2b^2c+4c^2)$

The factors are $2bc$ and $b^2+2b^2c+4c^2$

#Learn more

Factorise: $8a^3-24a^2+18a$

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