find the HCF of the terms of the expression 2b³c + 4b⁴c² + 16b²c²
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Answered by
6
Answer:
HCF=2b²c
Step-by-step explanation:
2b²c(b+2b²c+8c)
(2b²c) (b+2b²+8c)
it is the factor
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Answered by
0
Answer:
hcf= 2b square c
Step-by-step explanation:
2bsguare c ( b+2b square c +8c) (2b square c) (b+2b square c + 8c) it is the factoer
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