find the HCF of
two consecutive natural numbers
Answers
Answered by
0
Answer:
1
Step-by-step explanation:
Answered by
1
Answer:
HCF of any two consecutive natural numbers is 1. because the difference between two consecutive numbers is one & if the HCF is greater than one the the two consecutive numbers has to be divisible by that number which is not possible.
Step-by-step explanation:
It can only be 1. Why?
Let N and N+ 1 be the consecutive numbers. Let p be a common divisor of the two numbers.
Then N = a*p, where a is an integer. N+1 = b*p, where b is an integer.
So b*p - a*p = 1 = (b-a)*p
So b-a = 1/p
Given a and b are integers so is b-a. This means p cannot be greater than 1.
Answer: 1
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