Math, asked by rameshbhrigu, 9 months ago

find the HCF of
two consecutive natural numbers​

Answers

Answered by advocatedmdesai
0

Answer:

1

Step-by-step explanation:

Answered by mishtichak
1

Answer:

HCF of any two consecutive natural numbers is 1. because the difference between two consecutive numbers is one & if the HCF is greater than one the the two consecutive numbers has to be divisible by that number which is not possible.

Step-by-step explanation:

It can only be 1. Why?

Let N and N+ 1 be the consecutive numbers. Let p be a common divisor of the two numbers.

Then N = a*p, where a is an integer. N+1 = b*p, where b is an integer.

So b*p - a*p = 1 = (b-a)*p

So b-a = 1/p

Given a and b are integers so is b-a. This means p cannot be greater than 1.

Answer: 1

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