Question

find the hcf of (x-1) (x^2-9) and (x+3)(x^2-1)
pls answer this

Answer 1

HeYa❤️...

Answer:

Value of:

$= > (x - 1)(x {}^{2} - 9) \\ = x {}^{3} - 9x - x {}^{2} + 9...........(i)$

Value of:

$= > (x + 3)(x {}^{2} - 1) \\ = x {}^{3} - x + 3x {}^{2} - 3...........(ii)$

From equation (i) and (ii),

$x {}^{3} - 9x {}^{} - x {}^{2} + 9 = x,x,x,3,3,x,x,x,3,3 \\ x {}^{3} - x + 3x {}^{2} - 3 = x,x,x,x,3,x,x,3$

HCF => x, x, x, x, x, x, 3, 3 = 9x^6.

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