find the hcf of (x^3x-3+2) & (x^2-4x+3)
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Answer:
it is 3x in question
Step-by-step explanation:
H.C.F of (x2−3x+2) and (x2−4x+3);
Here to find the H.C.F. , we will use the method of factorisation as;
x2−3x+2 = x2−2x−x+2 = x(x−2)−1(x−2) = (x−1(x−2)
x2−4x+3= x2−3x−x+3 = x(x−3)−1(x−3) = (x−1)(x−3)
Now taking out the common term from the above factorisation we get H.C.F as;
= (x−1)
Therefore the H.C.F of (x3−3x+2) and (x2−4x+3) = (x−1)
ravi9848267328:
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