Question

find the HCF of x square - 16 and x cube + 64​

Answer 1

Answer:

$x^{2} -16=x^{2} -4^{2}=(x+4)(x-4)$

$x^{3} +64=x^{3}+4^{3}= (x+4)(x^{2} +4^{2}-4x)=(x+4)(x^{2}+16-4x)$

THEIR HCF IS = $(x+4)$

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