Question

Find the HCF of x³+4x²+x-6 and x³-1. Hence find for what value of 'x' both polynomials vanish.​

Answer 1

Answer:

Correct option is

A

(x-1)

x

2

−3x+2=x

2

−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x

2

−4x+3=x

2

−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

Option A

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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