find the HCF of1288 and 575 by using euclic division Lemma
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Answered by
2
Hey dear!!
Here is yr answer......
HCF of 1288 & 575
According to Euclid's division Algorithm....
a = bq+r
1288>575
1288 = 575 × 2 + 138
575 = 138 × 4 + 23
138 = 23 × 6 + 0
Here, divisor is the HCF
Therefore, HCF of 1288 & 575 = 23
Hope it hlpz...
Here is yr answer......
HCF of 1288 & 575
According to Euclid's division Algorithm....
a = bq+r
1288>575
1288 = 575 × 2 + 138
575 = 138 × 4 + 23
138 = 23 × 6 + 0
Here, divisor is the HCF
Therefore, HCF of 1288 & 575 = 23
Hope it hlpz...
Answered by
2
according to Euclid division Lemma ,
1288 = 575 . 2 + 138
575 = 138 . 4 + 23
138 = 23 . 6 + 0
therefore the HCF of 1288 and 575 is 23
1288 = 575 . 2 + 138
575 = 138 . 4 + 23
138 = 23 . 6 + 0
therefore the HCF of 1288 and 575 is 23
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