find the hcf of4052 and 12576 by using eculids division algorithm
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- using Euclid's division algorithm we get-
- 12576 = 4052 × 3+420
- 4052=420×9+272
- 420=272×1+148
- 272=148×1+124
- 148=124×1+24
- 124=24×5+4
- 24=4×6+0
since, remainder is 0 therefore HCF is the divisor 4
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