find the hcf of5325 and 8307
Answers
Answered by
7
8307= 5325×1+2982
5325= 2982×1+2343
2382= 2343×1+639
2343= 639×3+426
639= 426×1+213
426=213×2+0
so hcf = 213
5325= 2982×1+2343
2382= 2343×1+639
2343= 639×3+426
639= 426×1+213
426=213×2+0
so hcf = 213
vikramrajput:
esko pura calculation kar ke battao bhai
yhi pura calculation hai
thanks bhai
Euclid division algorithm
Similar questions