Question

find the hcf x2-1,x2-2x+1,x3+x2-2x​

Answer 1

Answer:

soln

1 exp= x²-1

     =(x+1)(x₋1)

2nd exp=x²-2x

             = x(x-2)

3rd exp= x³+x²-2x

           =x(x²+x-2)

            so hcf= 0

Step-by-step explanation:

Answer 2

Step-by-step explanation:

x2-1,x2-2x+1,x3+x2-2x