Question

Find the heat energy required to raise the temper
of 5 kg of water at 80°C to 100°C. (Specific h
water is 1 cal g-1°C-1)​

Answer 1

Answer:

Heat energy required is 42000 J

Step By Step Solution:

Mass of water = 5kg = 5000 g

Initial temperature (T₁) = 80°C

Initial temperature (T₂) = 100°C

Heat energy required is given by the formula

$\textbf{H}=\textbf{m}\times\textbf{c}\times\Delta\textbf{t}$

By substituting the given values,

$\Rightarrow \text{H}=\text{m}\times\text{c}\times\Delta\text{t}\\\\\Rightarrow \text{H}=5000\times1\times(100-80)\\\\\Rightarrow \text{H}=10000\text{ cal}$

Now, convert heat energy required into joules by using the conversion

$1\text{ cal}=4.2\text{Joules}$

$\Rightarrow 10\text{ kCal} = 10000\times4.2=42000\text{ J}$

$\boxed{\text{Heat energy required is 42000 J}}$