Question

Find the heat generated in calorie if a current of 1ampere is passed through a coil of resistance 836 ohm for 1 minute if (j=4.186)

Answer 1

Answer:

Answer of this question is 12000 cal

Answer 2

Answer:

11982.79 calories

Explanation:

The rate of heat generation in a nuclear core is directly proportional to the rate of fuel fission and the thermal neutron flux present. On a thermodynamic basis, the same heat generation is also associated with the fluid temperature difference across the core and the fluid mass flow through the core. Thus, the size of the reactor core is dependent on and limited by how much fluid can pass through the core to remove the generated thermal energy. Many other factors affect the amount of heat generated in the reactor core, but its limiting rate of production is based on how much energy the coolant can safely carry.

Mechanically generated heat can be defined as heat produced by mechanical processes involving the movement and deformation of matter. In this paper we will mainly focus on heat generated by deformation in elastoviscoplastic solids as well as frictional contact.

According to the question:

I= 1 ampere

R=836 ohms

T=1 minute=60 seconds

Heat is given as(in joules)=$I^2RT$

And in calories, it is given as=$\frac{I^2RT}{4.186}$

Hence heat generated in calories will be= $\frac{1^2*836*60}{4.186}$=11982.79 calories