Question

Find the heat required to convert 1g of ice

at 0°C to steam at 100°C. [Latent Heat of

fusion of ice = 80cal/g, specific heat

capacity of water = 1cal/g°C, Latent heat

of vaporisation of water = 536 cal/g.]​

Answer 1

Answer:

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Explanation:

Therefore, the heat required to convert ice at 0∘C into steam at 100∘C is equal to 716 cal.