Find The Height Above Earth Surface where 'g' Drops to 36% of g at surface (A) 3/2 r (B) 5/4 r² (C) 2/3 r (D) 4/5 r
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The acceleration due to gravity at height h is given by
g
′
=
(R+h)
2
gR
2
. . . . .(1)
The acceleration due to gravity decreases at height h decreases by 36%
g
′
=g−
100
36g
=
100
64
=0.64g. . . . . .(2)
From equation (1) and equation (2), we get
(R+h)
2
gR
2
=
100
64
g
(
R+h
R
)
2
=(
10
8
)
2
R+h
R
=
10
8
10R=8R+8h
2R=8R
h= 4/R
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