Find the height above the surface of earth where the value of acceleration due to gravity falls to
1% at the surface of the earth.
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Given : g h =1% g s
=0.01 g s
Using g h =g s
( R+hh ) 2
Or 0.01 g =g s
( R+hh ) 2
Or 0.1= R+hR
Or 0.1R+0.1h=R
⟹ h=9R
So, K=9
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