Question

Find the height at which g(d) becomes equal to g(h).​

Answer 1

Answer:

Correct option is

D

d=2h

Let the radius of the earth be  R and acceleration due to gravity at earth surface be  g.

Acceleration due to gravity at height  h above the earth surface, gh=g(1−R2h)

Acceleration due to gravity at depth  d below the earth surface, gd=g(1−Rd)

Now for gh=gd  we get, g(1−R2h) =g(1−Rd)

⇒  1−R2h=1−Rd

⇒  d=2h

Answer 2

Answer:

$Correct \ option \ is</p><p></p><p> \ D</p><p></p><p> \ d \ = \ 2h</p><p></p><p> \ Let \ the \ radius \ of \ the earth \ be \  R  \ and acceleration \ due \ to \ gravity \ at \ earth \ surface \ be \  g.</p><p></p><p>Acceleration \ due \ to \ gravity \ at \ height   \ habove the \ earth \ surface,  \ gh \ =g(1−R2h)</p><p></p><p>Acceleration \ due \ to \ gravity \ at \ depth \  dbelow the \ earth \ surface,  \ gd=g(1−Rd)</p><p></p><p>Now \ for  \ gh=gd  \ we get,  \ g(1−R2h)  \ =g(1−Rd)</p><p></p><p> \: ⇒  1−R2h=1−Rd</p><p></p><p> \: ⇒  d=2h</p><p></p><p>$

$\large{\blue{{\underline\color{blue}{\sf{hope \: it \: may \: help \: you}}}}}$