find the height at which the value of g reduces to g/2 ?
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at the 3200 km height the value of f will be half
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Effective acceleration due to gravity at a height h above the ground is given by,
g' = g ( R/R+h)²
R is the radius of the earth, and is equal to 6400km.
To find the height at which the value of g reduces to g/2
g/2 = g ( R/R+h)²
1/2 = ( R/R+h)²
1/√2 = R/R+h
R + h = √2 R
h = R ( √2 - 1)
Therefore, At a height ( √2 - 1) R, The value of g reduces to g/2.
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