Question

find the height corresponding to base BC of a right triangle ABC, right angled at A if AB=15cm,BC=39cm, and AC=36 cm

Answer 1

Answer:

the height corresponding to base BC ≈ 14

Step-by-step explanation:

From the figure, AD be the  height when base is BC

The area of right angled triangle with base 'b' and height 'h, is given by,

Area, A = 1/2bh

When base is AB = 15cm and height is AC = 36

Area, A1= 1/2*15*36

When base is BC = 39 cm and height is AD

Area, A2 = 1/2*36*AD

To find the height AD

We know that A1 and A2 are areas  of triangle ABC

Therefore A1 = A2

$\frac{1}{2}1*36*AD=\frac{1}{2}*15*36$

AD=13.84 ≈ 14 cm

Answer 2

Answer:

Height corresponding to Base BC is 13.846 cm

Step-by-step explanation:

Given

right angled triangle of AB=15 cm, BC=39 cm and AC=36 cm

We need to calculate the height corresponding to base BC

Area of right angled triangle with Base AB shall be = (1/2)xABxAC

i.e. (1/2)x15x36= 270 sq cm

Let AD is the perpendicular on Base BC

Now area of triangle with BC as base shall be = (1/2)xBCxAD

=(1/2)x39xAD

=19.5x AD

As we know both areas are of same triangle therefore,

19.5x AD= 270 sq cm

AD= 270/19.5

AD= 13.846 cm

Height corresponding to Base BC is 13.846 cm