Question

Find the height 'h' of the parallelogram whose area and base are 368 Sq.cm and 23cm respectively. ​

Answer 1

Area of parallelogram=Base×Height

⇒H=

6

30

=5cm

Answer 2

Answer :–

• Height (h) of a parallelogram = 16 cm.

Given :–

• Area of a parallelogram = 368 cm².
• Base of a parallelogram (b) = 23 cm.

To Find :–

• Height (h) of a parallelogram.

Solution :–

We know that,

• Area of a parallelogram = Base (b) × Height (h)

Given values are,

• Area of a parallelogram = 368 cm²
• Base (b) of a parallelogram = 23 cm.

Now, put the given values in the formula of area of a parallelogram.

So,

→ 23 cm × h = 368 cm²

→ h = $\sf \dfrac{\cancel{368} \: \cancel{ {cm}}^{2} }{\cancel{23} \: \cancel{cm}}$

→ h = $\sf \dfrac{16}{1} \: cm$

→ h = 16 cm

Hence,

The height (h) of a parallelogram is 16 cm.

Check :–

• Area of a parallelogram = Base (b) × Height (h)

• Area of a parallelogram = 368 cm²
• Base (b) = 23 cm.
• Height (h) = 16 cm.

Now, put all the values in the formula of area of a parallelogram.

→ 368 cm² = 23 cm × 16 cm

→ 368 cm² = 368 cm²

Since, the L.H.S. and the R.H.S. are equal.

So, the height (h) of a parallelogram is 16 cm is correct.