Question

find the height of a clyinder whose volume is 1.54cm³ and radius of a base is 70 cm​

Answer 1

Given:-

Volume of the cylinder = 1.54m³

Radius of the base (r),

= 70cm

= 0.7m

Volume of cylinder = πr²h

1.54 = 22/7•0.7²•h

1.54•7/22•0.7•0.7 = h

h = 1

Height = 1m Ans.

The height of the cylinder is 1m.

Answer 2

Given:-

• Volume of the cylinder is 1.54 cm³.
• Radius of the cylinder is 70 cm.

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To find:-

• Height of the cylinder.

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Solution:-

• Radius = 70 = 7/10

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Let,

• the height of the cylinder be h.

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☆Volume of cylinder = πr²h

⇛ 1.54 = πr²h

⇛ πr²h = 1.54

⇛ 22/7 × (7/10)² × h = 1.54

⇛ 22/7 × 7/10 × 7/10 × h = 154/100

⇛ 22×7/100 h = 154/100

⇛ 154/100 h = 154/100

⇛ 154h = 154

⇛ h = 154/154

⇛ h = 1 m

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Hence,

• the height of the cylinder is 1 m.

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☆Formulas related to Surface area and Volume:-

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$