Find the height of a cuboid whose perimeter of the base is 550 2 and lateral surface area is
2750 2.
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Area of the sheet required for making the box open at the top = 2(bh+ h1)+ lb
= 2 (1.25 × 0.65 + 0.65 × 1.5) + 1.5 × 1.25
= 2 (0.8125 + 0.975) + 1.875
= 2 × 1.7875 + 1.875
= 3.575 + 1.875
= 5.45 m2
= 2 (1.25 × 0.65 + 0.65 × 1.5) + 1.5 × 1.25
= 2 (0.8125 + 0.975) + 1.875
= 2 × 1.7875 + 1.875
= 3.575 + 1.875
= 5.45 m2
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