Question

find the height of a cylinder whose diameter is 42 and the area of its area of its curved surface is 11,880sq.cm​

Answer 1

Answer:

Diameter = 42, Height = 10

Radius (r) = 42/2 = 21

Curved Area of Cylinder = 2πrh = 2 × (22/7) × 21 × 10

= 1320 sq cm

Total Surface Area = 2πrh + 2πr²

= 1320 + [2 × (22/7) × 21²]

= 1320 + 2772

=4092 sq cm

THANKYOU

Answer 2

Answer:

$2\pi \: rh = 11880 \\ 2 \times \frac{22}{7} \times 21 \times h = 11880 \\ h = \frac{11880 \times 7}{22 \times 2 } \\ h = 180 \: cm$