Find the height of a parallellogram whose base is 8cm and area is 91.2 sq.
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2
Answer:
area of parallelogram =b×h
91.2cm =8cm×h
91.2÷8 =h
11.4 =h
Therfore required height is 11.4cm
Step-by-step explanation:
Answered by
3
GIVEN:
A parallelogram in which the Base = 8cm; Area = 91.2 cm²
TO FIND:
Height of the parallelogram
SOLUTION:
Area of any parallelogram is the product of the base and the height in it,
I.e, Area of a parallelogram = Base × Height
[∵ Base = 8cm and Area = 91.2 cm²]
==> 91.2 cm² = 8 × Height
==> Height = 91.2/8
= 114/10
= 11.4 cm
∴ Required height of IIgm is 11.4 cm
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