Question

find the height of a tower if the angle of elevation of its top from a point 100m away from its foot is 60 degree

Answer 1

Answer:

Let the height of the tower AC be h metres Given distance BC = 100 m, ∠ABC=60°

∴tan 60°  = AC/BC = h/100 ⇒ h = 100 X tan 60° = (100 X √3 )metre

= 100 X 1.732 = 173.2 m