Question

Find the height of a trapezium in which parallel sides are 25 cm 77 cm and non-parallel sides and 26 cm and 60 cm.
Given the area of the trapezium as 1644 cm^2.

Answer 1

area of trapezium = 1/2 × sum of parallel sides × height

1644 = 1/2 × ( 25 + 77) × h
= > 1644 × 2 / 102 = h

SO , h = 32.23 cm.

HOPE IT WILL HELP YOU. . . . . . . . . . .

PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! ! ! ! ! !

Answer 2

Draw a line from vertex C and parallel
to AD, which meet AB at E.

∵ AE II DC and AD II EC
∴ AECD is a parallelogram

EC = AD = 25 cm

AE = DC = 60 cm

EB = AB - AE
= 77 - 60
= 17 cm

Area △BEC

s = 25 + 26 + 17 / 2
= 34 cm

Area △BEC = √(34 * 9 * 8 * 17)
= 17 * 3 * 2 * 2
= 204 cm²

Let h cm is the length of perpendicular to EB.

Area △BEC = 1/2 * 17 * h
= 204 cm²

h = 204 * 2 / 17
= 24 cm Ans.

Area trap. ABCD = 1/2 * (60 + 77) * 24
= 137 * 12
= 1644 cm² Proved.