Question

Find the height of a trapezium in which parallel sides are 25 cm 77 cm and non-parallel sides and 26 cm and 60 cm.​

Answer 1

Answer:

CF = DF - CD

= ( 77 - 60 ) cm

= 17cm

For triangle BCF

Perimeter of the Traingle angled Traingle BCF = BC + BF + CF.

= (25+ 16+ 17)cm

=68cm.

Semiperimeter of the Traingle (s) = P upon 2 =

68

__ = 34 cm.

2

By heron formula is given in picture and continue is done here⬇

let h cm be the length of the perpendicular to CF.

1

Area of BCF = ___× CF × BE.

2

1

➳ 204 = ___ × 17 × h

2

204 × 2

➳ h = _________ = 24cm

14

1

Area of trapezium ABCD = __ [(60 + 77) +24]

=half (137 ×