Find the height of a trapezium, the sum of lengths of whose bases is 39 cm and whose area
is 65 cm
Answers
Answered by
10
Answer:
3.33 cm
Step-by-step explanation:
Given :
In a trapezium,
Sum of length of bases = 39 cm
Area = 65 cm²
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To Find :
Height = ?
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Solution :
\begin{gathered}\bf = > \: area \: = \: \frac{1}{2} \times \: ( \: sum \: of \: bases \: ) \: \times \: height \\ \\ = > \bf \: 65 \: = \: \frac{1}{2} \: \times \: 39 \: \times \: h \\ \\ = > \bf \: h \: = \: \frac{65 \: \times \: 2}{39} \\ \\ = > \bf \: h \: = \: 3.33 \: cm \:\end{gathered}=>area=21×(sumofbases)×height=>65=21×39×h=>h=3965×2=>h=3.33cm
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