Question

Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2. fast fast !!!!

Answer 1

Given :

• Sum of parallel sides = 60 cm

• Area of trapezium = 600 cm²

To find :

• Height of trapezium

Solution :

Formula of Area of trapezium = ½ × Sum of parallel sides × Height of trapezium

Substituting the given values :-

→ 600 = ½ × 60 × height of trapezium

→ 600 = 30 × height of trapezium

→ 600 ÷ 30 = height of trapezium

→ 60 ÷ 3 = height of trapezium

→ 20 = height of trapezium

Therefore, height of the trapezium = 20 cm

VERIFICATION :

We can verify the value of height of the trapezium by finding the area. If the area will be equal to 600 cm² as mentioned in the question then the value of height is right.

→ Area of trapezium = ½ × Sum of parallel sides × Height of trapezium

→ Substituting the given values :-

→ Area of trapezium = ½ × 60 × 20

→ Area of trapezium = 30 × 20

→ Area of trapezium = 600

Area of trapezium = 600 cm²

Hence, verified!

Answer 2

Step-by-step explanation:

Question:-

Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.

Answers:-

Let h be the height of trapezium.

Given:-

• Sum of bases of trapezium (b1 +b2 )= 60 cm

Solution:-

Area of trapezium =$600cm {}^{2}$

$⇒600= \frac{1}{2} ×(b1+b2)×h$

$⇒600= \frac{1}{2} ×60×h$

$⇒h= \frac{600}{60} ×2$

$⇒h=20$

∴ Height of trapezium =20 cm