Question

Find the height of a trapezium whose area is 65^2 and parallel sides are 13 cm and 26cm

Answer 1

Given that,

Area = 65 cm²

One of the parallel side's length = 13 cm

Length of second parallel side = 26 cm

To find,

Length of the height of a trapezium = ?

Formula needed,

Area of trapezium = $\frac{1}{2}$ (sum of parallel sides) * height

65 cm² = $\frac{1}{2} (13 + 26) \times h$

65 cm² = $\frac{1}{2} (39) \times h$

65 cm² = $\frac{1}{\cancel{2}} {\cancel{(39)}} \times h$

65 cm² = 19.5h

$\frac{65\:cm^2}{19.5\:cm}$ = h

$\frac{\cancel{65}}{\cancel{19.5}}$ = h

3.3 cm (approx) = h

$\boxed{Height = 3.3\:cm}$

Therefore, the height of trapezium is 3.3 cm approximately.

Answer 2

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